Bash Shell 날짜, 시간 yyyy-MM-dd

리눅스의 Bash Shell script 에서 날짜, 시간을 가져오는 법

 

1. 날짜

today = `data`
echo $today

today = $(date)
echo $today

 

2. yyyy-MM-dd 포맷적용하는 방법

today=`date +%Y-%m-%d`
echo $today

 

3. 시간만 출력

time=`date +%T`
echo $time

 

4. 특정날짜

yesterday=`date -d "-1 days"`
echo $yesterday

tommorrow=`date -d "+1 days"`
echo $tommorrow

5. 그 외 포맷

date +%a	Gives name of the weekday [Mon, Sun, Fri]
date +%A	Gives name of the weekday [Monday, Sunday, Friday]
date +%b	Gives name of the month [Jan, Feb, Mar]
date +%B	Gives name of the month [January, February, March]
date +%d	Displays day of the month [05]
date +%D	Displays current date MM/DD/YY format [11-01-21]
date +%F	Shows date in YYYY-MM-DD format [2021-11-01]
date +%H	Shows hour in 24-hour format [22]
date +%I	Shows hour in 12-hour format [11]
date +%j	Displays the day of the year [001 – 366]
date +%m	Displays the number of the month [01-12]
date +%M	Displays minutes [00-59]
date +%s	Unix time stamp
date +%S	Displays seconds [00-59]
date +%N	Displays in Nanoseconds
date +%T	Displays time as HH:MM:SS [in 24-hour format]
date +%u	Day of the week [1-7] 1 is Monday, 6 is Saturday
date +%U	Shows week number of the year [00-53]
date +%Y	Displays year YYYY [2021]
date +%Z	Displays Time zone

 

 

echo $(date "+%Y%m%d_%H%M%S")

이런식으로 쓸 수 있다!